Select the correct answer.

What is the approximate solution to this equation?

[tex]\[ 7 e^{6x} = 42 \][/tex]

A. [tex]\( x \approx 0.30 \)[/tex]
B. [tex]\( x \approx 1.00 \)[/tex]
C. [tex]\( x \approx 0.17 \)[/tex]
D. [tex]\( x \approx 1.79 \)[/tex]



Answer :

To solve the equation [tex]\( 7e^{6x} = 42 \)[/tex], we can follow these steps:

1. Isolate the exponential term:
[tex]\[ e^{6x} = \frac{42}{7} \][/tex]
Simplifying the right-hand side, we get:
[tex]\[ e^{6x} = 6 \][/tex]

2. Take the natural logarithm of both sides:
Taking the natural logarithm (ln) on both sides helps to deal with the exponential:
[tex]\[ \ln(e^{6x}) = \ln(6) \][/tex]

3. Simplify using logarithm properties:
Use the property [tex]\(\ln(e^{k}) = k \cdot \ln(e)\)[/tex] where [tex]\( \ln(e) = 1 \)[/tex]:
[tex]\[ 6x \cdot \ln(e) = \ln(6) \][/tex]
Simplifying further:
[tex]\[ 6x = \ln(6) \][/tex]

4. Solve for [tex]\( x \)[/tex]:
Divide both sides by 6:
[tex]\[ x = \frac{\ln(6)}{6} \][/tex]

The numerical approximation for [tex]\( x \)[/tex] using the given answer results in:
[tex]\[ x \approx 0.30 \][/tex]

Thus, the correct answer is:
[tex]\[ x \approx 0.30 \][/tex]