Instructions: Calculate the discriminant, then state the number and type of solutions.

[tex]\[
\begin{array}{l}
7x^2 + 10x + 3 = 0 \\
D = \square
\end{array}
\][/tex]

There is/are [tex]$\square$[/tex] [tex]$\square$[/tex] solution(s) to the quadratic equation with this discriminant.



Answer :

To solve the given quadratic equation [tex]\(7x^2 + 10x + 3 = 0\)[/tex], we need to follow these steps:

1. Identify the coefficients [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] from the quadratic equation [tex]\(ax^2 + bx + c = 0\)[/tex]:
- [tex]\(a = 7\)[/tex]
- [tex]\(b = 10\)[/tex]
- [tex]\(c = 3\)[/tex]

2. Calculate the discriminant ([tex]\(D\)[/tex]) using the formula:
[tex]\[ D = b^2 - 4ac \][/tex]

3. Substitute the values of [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] into the discriminant formula:
[tex]\[ D = (10)^2 - 4(7)(3) \][/tex]

4. Perform the calculations:
[tex]\[ 10^2 = 100 \][/tex]
[tex]\[ 4 \cdot 7 = 28 \][/tex]
[tex]\[ 28 \cdot 3 = 84 \][/tex]
[tex]\[ D = 100 - 84 = 16 \][/tex]

So, the discriminant [tex]\(D\)[/tex] is:
[tex]\[ D = 16 \][/tex]

Next, we interpret the value of the discriminant:

5. If [tex]\(D > 0\)[/tex], the quadratic equation has two distinct real solutions.
6. If [tex]\(D = 0\)[/tex], the quadratic equation has one real repeated solution.
7. If [tex]\(D < 0\)[/tex], the quadratic equation has two complex solutions.

Since [tex]\(D = 16\)[/tex] ([tex]\(D > 0\)[/tex]), the quadratic equation [tex]\(7x^2 + 10x + 3 = 0\)[/tex] has two real and distinct solutions.

Therefore, the final result is:

The discriminant [tex]\(D = 16\)[/tex]. There are 2 real and distinct solutions to the quadratic equation with this discriminant.