When the solution to [tex]$x^2-11x+5$[/tex] is expressed as [tex]$\frac{11 \pm \sqrt{r}}{2}$[/tex], what is the value of [tex][tex]$r$[/tex][/tex]?

[tex]x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

A. 2
B. 5
C. 101
D. 141



Answer :

To solve for the value of [tex]\( r \)[/tex] in the expression [tex]\(\frac{11 \pm \sqrt{r}}{2}\)[/tex] from the quadratic equation [tex]\( x^2 - 11x + 5 \)[/tex], let's follow these steps:

1. Identify the coefficients [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex] from the quadratic equation:
[tex]\[ a = 1, \quad b = -11, \quad c = 5 \][/tex]

2. Calculate the discriminant of the quadratic equation:
The discriminant formula for a quadratic equation [tex]\( ax^2 + bx + c = 0 \)[/tex] is given by:
[tex]\[ \text{Discriminant} = b^2 - 4ac \][/tex]

3. Substitute the values of [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex] into the discriminant formula:
[tex]\[ \text{Discriminant} = (-11)^2 - 4 \cdot 1 \cdot 5 \][/tex]
[tex]\[ \text{Discriminant} = 121 - 20 \][/tex]
[tex]\[ \text{Discriminant} = 101 \][/tex]

4. Interpret the discriminant in the context of the original question:
The question states that the solution is expressed as [tex]\(\frac{11 \pm \sqrt{r}}{2}\)[/tex]. This corresponds to the quadratic formula [tex]\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex].

Since the discriminant [tex]\( b^2 - 4ac \)[/tex] is what is under the square root in the quadratic formula, we equate this to [tex]\( r \)[/tex]. Therefore:
[tex]\[ r = 101 \][/tex]

Therefore, the value of [tex]\( r \)[/tex] is [tex]\( \boxed{101} \)[/tex].