Answer :
Sure, let's solve for the side lengths of the squares whose areas are given. We will use the relationship [tex]\( A = s^2 \)[/tex], where [tex]\( A \)[/tex] is the area of the square and [tex]\( s \)[/tex] is the side length. Given the areas, we will find the side lengths by taking the square root of each area.
1. For an area of 14 in²:
[tex]\[ s = \sqrt{14} \approx 3.742 \][/tex]
So, the side length for an area of 14 in² is approximately 3.742 inches.
2. For an area of 28 in²:
[tex]\[ s = \sqrt{28} \approx 5.292 \][/tex]
Thus, the side length for an area of 28 in² is approximately 5.292 inches.
3. For an area of 49 in²:
[tex]\[ s = \sqrt{49} = 7.0 \][/tex]
Here, the side length for an area of 49 in² is exactly 7.0 inches.
4. For an area of 98 in²:
[tex]\[ s = \sqrt{98} \approx 9.899 \][/tex]
Therefore, the side length for an area of 98 in² is approximately 9.899 inches.
To summarize:
- The side length for an area of 14 in² is approximately 3.742 inches.
- The side length for an area of 28 in² is approximately 5.292 inches.
- The side length for an area of 49 in² is 7.0 inches.
- The side length for an area of 98 in² is approximately 9.899 inches.
1. For an area of 14 in²:
[tex]\[ s = \sqrt{14} \approx 3.742 \][/tex]
So, the side length for an area of 14 in² is approximately 3.742 inches.
2. For an area of 28 in²:
[tex]\[ s = \sqrt{28} \approx 5.292 \][/tex]
Thus, the side length for an area of 28 in² is approximately 5.292 inches.
3. For an area of 49 in²:
[tex]\[ s = \sqrt{49} = 7.0 \][/tex]
Here, the side length for an area of 49 in² is exactly 7.0 inches.
4. For an area of 98 in²:
[tex]\[ s = \sqrt{98} \approx 9.899 \][/tex]
Therefore, the side length for an area of 98 in² is approximately 9.899 inches.
To summarize:
- The side length for an area of 14 in² is approximately 3.742 inches.
- The side length for an area of 28 in² is approximately 5.292 inches.
- The side length for an area of 49 in² is 7.0 inches.
- The side length for an area of 98 in² is approximately 9.899 inches.