To convert the length of a table from feet to meters and centimeters, we can follow these steps:
### Step 1: Convert feet to meters
Start with the length of the table in feet, which is [tex]\( 27.92 \, \text{feet} \)[/tex]. We know that [tex]\( 1 \, \text{foot} \)[/tex] is equivalent to [tex]\( 0.3048 \, \text{meters} \)[/tex].
[tex]\[
27.92 \, \text{feet} \times 0.3048 \, \text{meters/foot} = 8.510016 \, \text{meters}
\][/tex]
Therefore, [tex]\( 27.92 \, \text{feet} \)[/tex] is equivalent to [tex]\( 8.510016 \, \text{meters} \)[/tex].
### Step 2: Convert meters to centimeters
Next, we want to convert the length in meters to centimeters. We know that [tex]\( 1 \, \text{meter} \)[/tex] is equivalent to [tex]\( 100 \, \text{centimeters} \)[/tex].
[tex]\[
8.510016 \, \text{meters} \times 100 \, \text{cm/meter} = 851.0016 \, \text{centimeters}
\][/tex]
Therefore, [tex]\( 8.510016 \, \text{meters} \)[/tex] is equivalent to [tex]\( 851.0016 \, \text{centimeters} \)[/tex].
### Step 3: Separate into meters and centimeters
To express this length in terms of meters and centimeters separately, we need to determine how many whole meters and how many additional centimeters there are.
- Whole meters: [tex]\( 8 \, \text{meters} \)[/tex] (since [tex]\( 851.0016 \, \text{cm} \)[/tex] contains 8 full meters)
- Remaining centimeters: [tex]\( 51 \, \text{cm} \)[/tex] (since the remainder is [tex]\( 851.0016 \, \text{cm} \mod 100 \)[/tex])
Therefore, [tex]\( 851.0016 \, \text{cm} \)[/tex] can be expressed as [tex]\( 8 \, \text{meters} \)[/tex] and approximately [tex]\( 51 \, \text{centimeters} \)[/tex] when rounded to the nearest centimeter.
### Conclusion
Putting it all together:
- 27.92 feet is approximately 8.51 meters.
- This can also be expressed as 8 meters and 51 centimeters.
So, the final answer converted from 27.92 feet is either:
- [tex]\( A \)[/tex] [tex]\( 8.51 \, \text{meters} \)[/tex]
- [tex]\( C \)[/tex] [tex]\( 8 \, \text{meters and } 51 \, \text{centimeters} \)[/tex]
Both [tex]\( A \)[/tex] and [tex]\( C \)[/tex] are correct ways to represent the conversion, but since the problem specifically asks to round the answer to the nearest centimeter, the most precise final answer is:
[tex]\( \boxed{8 \, \text{meters and } 51 \, \text{centimeters}} \)[/tex]
