The mass of a sample of sodium bicarbonate is 2.1 kilograms (kg). There are 1,000 grams (g) in 1 kg, and [tex]1 \times 10^9[/tex] nanograms (ng) in 1 g.

What is the mass of this sample in ng?

A. [tex]2.1 \times 10^3[/tex] ng

B. [tex]2.1 \times 10^6[/tex] ng

C. [tex]2.1 \times 10^9[/tex] ng

D. [tex]2.1 \times 10^{12}[/tex] ng



Answer :

To determine the mass of a sample of sodium bicarbonate in nanograms (ng) when given the mass in kilograms (kg), we will follow these steps:

1. Conversion from kilograms to grams:
- We know that [tex]\(1 \, \text{kg}\)[/tex] is equal to [tex]\(1,000 \, \text{grams}\)[/tex] (g).
- Therefore, to convert the given mass of 2.1 kilograms to grams, we multiply the mass in kilograms by 1,000.
[tex]\[ 2.1 \, \text{kg} \times 1,000 \, \text{g/kg} = 2,100 \, \text{g} \][/tex]

2. Conversion from grams to nanograms:
- We also know that [tex]\(1 \, \text{gram}\)[/tex] is equal to [tex]\(1 \times 10^9 \, \text{nanograms}\)[/tex] (ng).
- To convert the mass from grams to nanograms, we multiply the mass in grams by [tex]\(1 \times 10^9\)[/tex].
[tex]\[ 2,100 \, \text{g} \times 1 \times 10^9 \, \text{ng/g} = 2.1 \times 10^{12} \, \text{ng} \][/tex]

Combining these conversions, we find that the mass of the sodium bicarbonate sample in nanograms is given by:
[tex]\[ 2.1 \, \text{kg} = 2.1 \times 10^{12} \, \text{ng} \][/tex]

Thus, the correct option is:
[tex]\[ \boxed{2.1 \times 10^{12} \, \text{ng}} \][/tex]