Use the remainder theorem to find [tex]$P(-2)$[/tex] for [tex]$P(x) = -2x^3 - 4x^2 - 9$[/tex].

Specifically, give the quotient and the remainder for the associated division and the value of [tex][tex]$P(-2)$[/tex][/tex].

Quotient [tex]= \ \square[/tex]

Remainder [tex]= \ \square[/tex]

[tex]P(-2) = \ \square[/tex]



Answer :

To find [tex]\( P(-2) \)[/tex] for [tex]\( P(x) = -2x^3 - 4x^2 - 9 \)[/tex] using the remainder theorem, we follow these steps:

1. Identify the polynomial:
[tex]\[ P(x) = -2x^3 - 4x^2 - 9 \][/tex]

2. Use Polynomial Long Division (or Synthetic Division):
We need to divide [tex]\( P(x) \)[/tex] by [tex]\( (x + 2) \)[/tex] to find the quotient and the remainder.

We start the division:
[tex]\[ \frac{-2x^3 - 4x^2 - 9}{x + 2} \][/tex]

3. Perform the division step-by-step:

- The leading term of the quotient is determined by dividing the leading term of the dividend by the leading term of the divisor:
[tex]\[ -2x^3 \div x = -2x^2 \][/tex]
- Multiply the entire divisor by this leading term:
[tex]\[ (-2x^2)(x + 2) = -2x^3 - 4x^2 \][/tex]
- Subtract this from the original polynomial:
[tex]\[ (-2x^3 - 4x^2 - 9) - (-2x^3 - 4x^2) = -9 \][/tex]

At this point, the remainder is [tex]\(-9\)[/tex], and we have no more terms to divide.

So, the quotient is:
[tex]\[ -2x^2 \][/tex]
And the remainder is:
[tex]\[ -9 \][/tex]

4. Summary of Division:
The quotient of the division is:
[tex]\[ \text{Quotient} = -2x^2 \][/tex]
The remainder of the division is:
[tex]\[ \text{Remainder} = -9 \][/tex]

5. Apply the Remainder Theorem:
According to the Remainder Theorem, the remainder when [tex]\( P(x) \)[/tex] is divided by [tex]\( x + 2 \)[/tex] is [tex]\( P(-2) \)[/tex].

Therefore,
[tex]\[ P(-2) = -9 \][/tex]

Thus, the final answer is:
[tex]\[ \text{Quotient} = -2x^2 \][/tex]
[tex]\[ \text{Remainder} = -9 \][/tex]
[tex]\[ P(-2) = -9 \][/tex]