At a museum cafe, you can get a pre-made boxed lunch with a sandwich, fruit, and drink for only [tex]\$3[/tex].

- The sandwiches are made with either turkey or ham.
- The fruit is either an apple or an orange.
- The drink is either bottled water or juice.

The number of boxes they make for every possible combination is the same. If you randomly choose one of the boxed lunches without knowing the contents, what is the probability you will get a turkey sandwich and a bottle of water in your box?

A. [tex]\frac{1}{8}[/tex]
B. [tex]\frac{1}{3}[/tex]
C. [tex]\frac{1}{4}[/tex]
D. [tex]\frac{1}{2}[/tex]



Answer :

Let's break down the problem step by step.

1. Identify the choices for each category in the boxed lunch:

- Sandwich options: There are two choices, turkey and ham.
- Fruit options: There are two choices, apple and orange.
- Drink options: There are two choices, bottled water and juice.

2. Calculate the total number of possible combinations:

To find the total number of different boxed lunches possible, we multiply the number of choices for each category together:

[tex]\[ \text{Total combinations} = (\text{Number of sandwich options}) \times (\text{Number of fruit options}) \times (\text{Number of drink options}) \][/tex]

Substituting the values, we get:

[tex]\[ \text{Total combinations} = 2 \times 2 \times 2 = 8 \][/tex]

This means there are 8 different possible combinations of boxed lunches.

3. Determine the number of favorable outcomes:

We are interested in the boxed lunch that includes a turkey sandwich and bottled water. Let's see how many such combinations are possible:

- For the sandwich: turkey (1 option)
- For the fruit: it can either be apple or orange (2 options)
- For the drink: bottled water (1 option)

So, there are:

[tex]\[ \text{Number of favorable outcomes} = 1 (\text{turkey}) \times 2 (\text{fruit}) \times 1 (\text{bottled water}) = 1 \][/tex]

4. Calculate the probability:

The probability of an event is given by:

[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \][/tex]

Plugging in the values:

[tex]\[ \text{Probability} = \frac{1}{8} \][/tex]

Therefore, the probability that you will get a boxed lunch with a turkey sandwich and bottled water is:

[tex]\[ \boxed{\frac{1}{8}} \][/tex]