Certainly! Let's match each equation with its correct solution.
### Equations and Solutions:
1. [tex]\( x - 6 = -4 \)[/tex]
- To solve for [tex]\(x\)[/tex], add 6 to both sides:
[tex]\[
x - 6 + 6 = -4 + 6 \implies x = 2
\][/tex]
2. [tex]\( x + 3 = -7 \)[/tex]
- To solve for [tex]\(x\)[/tex], subtract 3 from both sides:
[tex]\[
x + 3 - 3 = -7 - 3 \implies x = -10
\][/tex]
3. [tex]\( 5x = -2 \)[/tex]
- To solve for [tex]\(x\)[/tex], divide both sides by 5:
[tex]\[
5x \div 5 = -2 \div 5 \implies x = -0.4
\][/tex]
4. [tex]\( 0.5x = 5 \)[/tex]
- To solve for [tex]\(x\)[/tex], divide both sides by 0.5:
[tex]\[
0.5x \div 0.5 = 5 \div 0.5 \implies x = 10
\][/tex]
### Matching the Equations with Solutions:
- [tex]\( x - 6 = -4 \)[/tex] [tex]\(\rightarrow x = 2\)[/tex]
- [tex]\( x + 3 = -7 \)[/tex] [tex]\(\rightarrow x = -10\)[/tex]
- [tex]\( 5x = -2 \)[/tex] [tex]\(\rightarrow x = -0.4\)[/tex]
- [tex]\( 0.5x = 5 \)[/tex] [tex]\(\rightarrow x = 10\)[/tex]
So the correct matching of each equation with its solution is:
[tex]\[
\begin{array}{cccc}
\text{Equation} & \quad & \text{Solution} & \quad \\
x - 6 = -4 & \rightarrow & x = 2 & \square \\
x + 3 = -7 & \rightarrow & x = -10 & \square \\
5x = -2 & \rightarrow & x = -0.4 & \square \\
0.5x = 5 & \rightarrow & x = 10 & \square\\
\end{array}
\][/tex]
