Keith used the following steps to find the inverse of [tex]\( f \)[/tex], but he thinks he made an error.

\begin{tabular}{|l|c|l|}
\hline
Step 1 & [tex]\( f(x)=7x+5 \)[/tex] & given \\
\hline
Step 2 & [tex]\( y=7x+5 \)[/tex] & Change [tex]\( f(x) \)[/tex] to [tex]\( y \)[/tex]. \\
\hline
Step 3 & [tex]\( x=7y+5 \)[/tex] & Switch [tex]\( x \)[/tex] and [tex]\( y \)[/tex]. \\
\hline
Step 4 & [tex]\( x+5=7y \)[/tex] & Add 5 to each side. \\
\hline
Step 5 & [tex]\( \frac{x+5}{7}=y \)[/tex] & Divide each side by 7. \\
\hline
Step 6 & [tex]\( \frac{x+5}{7}=g(x) \)[/tex] & Change [tex]\( y \)[/tex] to [tex]\( g(x) \)[/tex]. \\
\hline
Step 7 & [tex]\( g(x)=\frac{x+5}{7} \)[/tex] & Switch sides of the equation. \\
\hline
\end{tabular}

What mistake, if any, did Keith make?

A. Keith did not make any errors.

B. In step 4, Keith should have subtracted 5 from each side.

C. In step 5, Keith should have multiplied each side of the equation by 7.

D. In step 6, Keith should have switched [tex]\( x \)[/tex] and [tex]\( y \)[/tex].



Answer :

Let's go through Keith's steps carefully to check his work on finding the inverse function of [tex]\( f(x) = 7x + 5 \)[/tex].

Step-by-step solution:

1. Step 1: [tex]\( f(x) = 7x + 5 \)[/tex]
This is the function given to us.

2. Step 2: [tex]\( y = 7x + 5 \)[/tex]
Replacing [tex]\( f(x) \)[/tex] with [tex]\( y \)[/tex] is a standard step in finding the inverse function.

3. Step 3: [tex]\( x = 7y + 5 \)[/tex]
Switching [tex]\( x \)[/tex] and [tex]\( y \)[/tex] is also correct as we seek the inverse function [tex]\( y \)[/tex] (now called [tex]\( g(x) \)[/tex]), which essentially reverses the roles of [tex]\( x \)[/tex] and [tex]\( y \)[/tex] in the original function.

4. Step 4: [tex]\( x + 5 = 7y \)[/tex]
Here Keith has made an algebraic manipulation; however, the correct step to isolate [tex]\( y \)[/tex] would be to subtract 5 from both sides, not add. This step should have been:
[tex]\[ x - 5 = 7y \][/tex]

5. Step 5: [tex]\(\frac{x + 5}{7} = y\)[/tex]
Since the correct step 4 should have been [tex]\( x-5 = 7y \)[/tex], dividing by 7 would give:
[tex]\[ y = \frac{x - 5}{7} \][/tex]

6. Step 6: [tex]\(\frac{x + 5}{7} = g(x) \)[/tex]
Substituting [tex]\( y \)[/tex] with [tex]\( g(x) \)[/tex] is typical when expressing the inverse function. However, since the expression in Step 5 was incorrect, this substitution, while typical, is based on an incorrect prior step.

7. Step 7: [tex]\( g(x) = \frac{x + 5}{7} \)[/tex]
Switching sides of the equation is usually done for clarity, displaying the function [tex]\( g(x) \)[/tex].

Given the steps and the analysis, we see that Keith's initial mistake happened at Step 4 where he added instead of subtracting 5. Thus, Keith’s correct working should look like this:

1. [tex]\( f(x) = 7x + 5 \)[/tex]
2. [tex]\( y = 7x + 5 \)[/tex]
3. [tex]\( x = 7y + 5 \)[/tex]
4. [tex]\( x - 5 = 7y \)[/tex] (subtract 5 from both sides)
5. [tex]\(\frac{x - 5}{7} = y \)[/tex] (divide both sides by 7)
6. [tex]\( g(x) = \frac{x - 5}{7} \)[/tex] (replace [tex]\( y \)[/tex] with [tex]\( g(x) \)[/tex])

Keith should have subtracted 5 in step 4, not added.

Therefore, the correct answer: B. In step 4, Keith should have subtracted 5 from each side.