Answer :
Lets see:
[tex] \frac{3}{8} + \frac{3}{8} + \frac{3}{8} = \frac{9}{8} = 1\frac{1}{8} [/tex] which is more than 1, but....
[tex] \frac{3}{8} + \frac{3}{8} = \frac{6}{8} [/tex]
The answer is 2
[tex]1= \frac{8}{8} [/tex]
[tex] \frac{8}{8} - \frac{6}{8} = \frac{2}{8} [/tex]
The answer is 2 with a remainder of 2/8 or 1/4 or 0.25
[tex] \frac{3}{8} + \frac{3}{8} + \frac{3}{8} = \frac{9}{8} = 1\frac{1}{8} [/tex] which is more than 1, but....
[tex] \frac{3}{8} + \frac{3}{8} = \frac{6}{8} [/tex]
The answer is 2
[tex]1= \frac{8}{8} [/tex]
[tex] \frac{8}{8} - \frac{6}{8} = \frac{2}{8} [/tex]
The answer is 2 with a remainder of 2/8 or 1/4 or 0.25
The number of 3/8's that are in 1 is [tex]2\frac{2}{3}[/tex]
From the question,
We are to determine the number of 3/8's that are in 1.
To do this, we will divide 1 by 3/8
The division operation is carried out as shown below
[tex]1 \div \frac{3}{8}[/tex]
This becomes
[tex]1 \times \frac{8}{3}[/tex]
= [tex]\frac{8}{3}[/tex]
= [tex]2\frac{2}{3}[/tex]
Hence, the number of 3/8's that are in 1 is [tex]2\frac{2}{3}[/tex]
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