Juliana had [tex]$\$[/tex]96[tex]$, which is eight times as much money as Al had. How much money did Al have? Select the correct solution method below, representing Al's money with $[/tex]x[tex]$.

A. $[/tex]\frac{x}{8}=96[tex]$. Multiply both sides by 8. Al had $[/tex]\[tex]$768$[/tex].

B. [tex]$x+8=96$[/tex]. Subtract 8 from both sides. Al had [tex]$\$[/tex]88[tex]$.

C. $[/tex]8x=96[tex]$. Divide both sides by 8. Al had $[/tex]\[tex]$12$[/tex].

D. [tex]$x-8=96$[/tex]. Add 8 to both sides. Al had [tex]$\$[/tex]104$.



Answer :

To determine how much money Al had, we need to start by understanding the relationship given in the problem. The problem states that Juliana had [tex]$\$[/tex] 96[tex]$, which is eight times as much money as Al had. We can represent this relationship with the equation \(8x = 96\). To solve for \(x\), we need to isolate \(x\). Here’s the step-by-step solution: 1. We have the equation \(8x = 96\). 2. To solve for \(x\), we need to get \(x\) by itself on one side of the equation. We can do this by dividing both sides of the equation by 8. 3. When we divide both sides by 8, we get: \[ x = \frac{96}{8} \] 4. Simplifying the right side, we get: \[ x = 12 \] Therefore, Al had $[/tex]\[tex]$ 12$[/tex]. The correct solution method is described in option C:

C. [tex]\(8x = 96\)[/tex]. Divide both sides by 8. Al had [tex]$\$[/tex] 12$.