Alejandro surveyed his classmates to determine who has ever gone surfing and who has ever gone snowboarding. Let [tex]$A$[/tex] be the event that the person has gone surfing, and let [tex]$B$[/tex] be the event that the person has gone snowboarding.

\begin{tabular}{|c|c|c|c|}
\hline & \begin{tabular}{c}
Has \\
Snowboarded
\end{tabular} & \begin{tabular}{c}
Never \\
Snowboarded
\end{tabular} & Total \\
\hline Has Surfed & 36 & 189 & 225 \\
\hline Never Surfed & 12 & 63 & 75 \\
\hline Total & 48 & 252 & 300 \\
\hline
\end{tabular}

Which statement is true about whether [tex]$A$[/tex] and [tex]$B$[/tex] are independent events?

A. [tex]$A$[/tex] and [tex]$B$[/tex] are independent events because [tex]$P(A \mid B)=P(A)=0.16$[/tex].

B. [tex]$A$[/tex] and [tex]$B$[/tex] are independent events because [tex]$P(A \mid B)=P(A)=0.75$[/tex].

C. [tex]$A$[/tex] and [tex]$B$[/tex] are not independent events because [tex]$P(A \mid B)=0.16$[/tex] and [tex]$P(A)=0.75$[/tex].

D. [tex]$A$[/tex] and [tex]$B$[/tex] are not independent events because [tex]$P(A \mid B)=0.75$[/tex] and [tex]$P(A)=0.16$[/tex].



Answer :

To determine whether the events [tex]\( A \)[/tex] (a person has gone surfing) and [tex]\( B \)[/tex] (a person has gone snowboarding) are independent, we need to analyze their probabilities and see if they satisfy the condition for independence: [tex]\( P(A \mid B) = P(A) \)[/tex].

Let’s examine the data and calculate the required probabilities step-by-step.

### Step 1: Extract the Totals

Given the table, we have:
- Total number of people surveyed: [tex]\(300\)[/tex]
- Number of people who have surfed ([tex]\(A\)[/tex]): [tex]\(225\)[/tex]
- Number of people who have snowboarded ([tex]\(B\)[/tex]): [tex]\(48\)[/tex]
- Number of people who have both surfed and snowboarded ([tex]\(A \cap B\)[/tex]): [tex]\(36\)[/tex]

### Step 2: Calculate [tex]\( P(A) \)[/tex]

The probability that a person has gone surfing, [tex]\( P(A) \)[/tex], is the ratio of the number of people who have surfed to the total number of people:

[tex]\[ P(A) = \frac{\text{Number of people who have surfed}}{\text{Total number of people}} = \frac{225}{300} = 0.75 \][/tex]

### Step 3: Calculate [tex]\( P(B) \)[/tex]

The probability that a person has gone snowboarding, [tex]\( P(B) \)[/tex], is:

[tex]\[ P(B) = \frac{\text{Number of people who have snowboarded}}{\text{Total number of people}} = \frac{48}{300} = 0.16 \][/tex]

### Step 4: Calculate [tex]\( P(A \cap B) \)[/tex]

The probability that a person has both surfed and snowboarded, [tex]\( P(A \cap B) \)[/tex], is:

[tex]\[ P(A \cap B) = \frac{\text{Number of people who have both surfed and snowboarded}}{\text{Total number of people}} = \frac{36}{300} = 0.12 \][/tex]

### Step 5: Calculate [tex]\( P(A \mid B) \)[/tex]

The conditional probability that a person has surfed given that they have snowboarded, [tex]\( P(A \mid B) \)[/tex], is:

[tex]\[ P(A \mid B) = \frac{P(A \cap B)}{P(B)} = \frac{0.12}{0.16} = 0.75 \][/tex]

### Step 6: Compare [tex]\( P(A \mid B) \)[/tex] and [tex]\( P(A) \)[/tex]

We have:
- [tex]\( P(A \mid B) = 0.75 \)[/tex]
- [tex]\( P(A) = 0.75 \)[/tex]

Since [tex]\( P(A \mid B) = P(A) \)[/tex], the events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are independent.

### Conclusion

The correct statement is:

[tex]\[ A \text{ and } B \text{ are independent events because } P(A \mid B) = P(A) = 0.75. \][/tex]