Select the correct answer.

Assuming no denominator equals zero, which expression is equivalent to the given expression?

[tex]\frac{4 m^2-9}{2 m^2-13 m+15}[/tex]

A. [tex]\frac{2 m+3}{m+5}[/tex]
B. [tex]\frac{2 m-3}{m+5}[/tex]
C. [tex]\frac{2 m+3}{m-5}[/tex]
D. [tex]\frac{2 m-3}{m-5}[/tex]



Answer :

To determine which expression is equivalent to the given expression [tex]\(\frac{4m^2 - 9}{2m^2 - 13m + 15}\)[/tex], we need to simplify the provided fraction step by step.

1. Factor the numerator:
The numerator is [tex]\(4m^2 - 9\)[/tex]. This expression is a difference of squares, which can be factored as follows:
[tex]\[ 4m^2 - 9 = (2m)^2 - 3^2 = (2m - 3)(2m + 3) \][/tex]

2. Factor the denominator:
The denominator is [tex]\(2m^2 - 13m + 15\)[/tex]. We factor this quadratic expression by finding two numbers that multiply to [tex]\(2 \times 15 = 30\)[/tex] and add up to [tex]\(-13\)[/tex]. These numbers are [tex]\(-3\)[/tex] and [tex]\(-10\)[/tex]. Using these numbers, we can rewrite and factor the denominator:
[tex]\[ 2m^2 - 13m + 15 = 2m^2 - 3m - 10m + 15 = m(2m - 3) - 5(2m - 3) = (m - 5)(2m - 3) \][/tex]

3. Simplify the fraction:
Having factored both the numerator and the denominator, we replace the original expression with its factored form:
[tex]\[ \frac{4m^2 - 9}{2m^2 - 13m + 15} = \frac{(2m - 3)(2m + 3)}{(m - 5)(2m - 3)} \][/tex]

Notice that the [tex]\((2m - 3)\)[/tex] term appears in both the numerator and the denominator, allowing us to cancel it:

[tex]\[ \frac{(2m - 3)(2m + 3)}{(m - 5)(2m - 3)} = \frac{2m + 3}{m - 5} \][/tex]

Therefore, the expression equivalent to [tex]\(\frac{4m^2 - 9}{2m^2 - 13m + 15}\)[/tex] is [tex]\(\frac{2m + 3}{m - 5}\)[/tex].

Among the given choices, the correct answer is:

[tex]\(\frac{2m + 3}{m - 5}\)[/tex]