Solution:
Given : ABCD is a square and BGHE is a rectangle.
To prove : Area of (square ABCD = rectangle BGHE)
Proof:
[tex]\text{1. Area of (square ABCD = parallelogram BCFE$})[/tex]
[tex][\text{Square ABCD and parallelogram BCFE are on same base CB and both of $}[/tex]
[tex]\text{their heights is CD.]$}[/tex]
[tex]\text{2. Area of (rectangle BGHE = par. BCFE)$}[/tex]
[tex]\text{[Rectangle BGHE and parallelogram BCFE are on same base BE, and both$}[/tex]
[tex]\text{of their heights is EH.]$}[/tex]
[tex]\text{3. Area of (Square ABCD = rectangle BGHE)$}[/tex]
[tex][\text{From statements 1 and 2.$}][/tex]
Hope you got this!
