Identify the solutions to the quadratic equation.

[tex]\[ x^2 + 4x - 21 = 0 \][/tex]

Check all that apply.

A. [tex]\( x = -7 \)[/tex]

B. [tex]\( x = 3 \)[/tex]

C. [tex]\( x = 4 \)[/tex]

D. [tex]\( x = 21 \)[/tex]

E. [tex]\( x = -5 \)[/tex]



Answer :

To determine the solutions to the quadratic equation [tex]\( x^2 + 4x - 21 = 0 \)[/tex], we need to solve the equation and see which of the given options are correct.

### Step-by-Step Solution:

1. Solve the Quadratic Equation:
The quadratic equation given is [tex]\( x^2 + 4x - 21 = 0 \)[/tex].
We'll start by factoring the quadratic equation.

2. Factoring:
To factor [tex]\( x^2 + 4x - 21 \)[/tex], we need to find two numbers that multiply to [tex]\(-21\)[/tex] (the constant term) and add up to [tex]\(4\)[/tex] (the coefficient of the linear term).

Those two numbers are:
- [tex]\( -3 \)[/tex] and [tex]\( 7 \)[/tex]

Therefore, we can write:
[tex]\[ x^2 + 4x - 21 = (x + 7)(x - 3) = 0 \][/tex]

3. Finding the Roots:
Now that we have factored the quadratic equation, we set each factor to zero and solve for [tex]\( x \)[/tex]:

[tex]\[ (x + 7) = 0 \quad \text{or} \quad (x - 3) = 0 \][/tex]

Solving these gives us:
[tex]\[ x + 7 = 0 \quad \Rightarrow \quad x = -7 \][/tex]
[tex]\[ x - 3 = 0 \quad \Rightarrow \quad x = 3 \][/tex]

So the solutions to the quadratic equation are [tex]\( x = -7 \)[/tex] and [tex]\( x = 3 \)[/tex].

### Checking the Given Options:

Let's see which of the given options match the solutions we found:

- Option A: [tex]\( x = -7 \)[/tex]
This matches our solution.
Correct

- Option B: [tex]\( x = 3 \)[/tex]
This matches our solution.
Correct

- Option C: [tex]\( x = 4 \)[/tex]
This is not one of our solutions.
Incorrect

- Option D: [tex]\( x = 21 \)[/tex]
This is not one of our solutions.
Incorrect

- Option E: [tex]\( x = -5 \)[/tex]
This is not one of our solutions.
Incorrect

### Conclusion:
The correct solutions to the quadratic equation [tex]\( x^2 + 4x - 21 = 0 \)[/tex] that match the given options are:
- Option A: [tex]\( x = -7 \)[/tex]
- Option B: [tex]\( x = 3 \)[/tex]