If the coefficient of kinetic friction between a 343 N crate and the floor is 0.30, what is the force of friction experienced?

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Answer :

To determine the force of friction experienced by the crate, we can follow these steps:

1. Identify the Given Values:
- The weight of the crate, [tex]\( W \)[/tex], is given as 343 Newtons (N).
- The coefficient of kinetic friction, [tex]\( \mu_k \)[/tex], is provided as 0.30.

2. Understand the Relevant Formula:
The formula to calculate the force of friction, [tex]\( f_k \)[/tex], is:

[tex]\[ f_k = \mu_k \times N \][/tex]

where:
- [tex]\( f_k \)[/tex] is the force of kinetic friction.
- [tex]\( \mu_k \)[/tex] is the coefficient of kinetic friction.
- [tex]\( N \)[/tex] is the normal force.

3. Compute the Normal Force:
In this scenario, the normal force [tex]\( N \)[/tex] is equal to the weight of the crate since the crate is on a horizontal surface with no additional vertical forces acting on it. Thus:

[tex]\[ N = W = 343 \text{ N} \][/tex]

4. Substitute the Values into the Formula:
We can plug the given values into the formula for the force of kinetic friction:

[tex]\[ f_k = \mu_k \times N = 0.30 \times 343 \text{ N} \][/tex]

5. Calculate the Force of Friction:
Performing the multiplication gives:

[tex]\[ f_k = 0.30 \times 343 \text{ N} = 102.90 \text{ N} \][/tex]

Hence, the force of friction experienced by the crate is approximately [tex]\( 102.90 \)[/tex] Newtons.