Let's determine the element based on its electron configuration by summing up the number of electrons in each subshell.
The given electron configuration is:
[tex]\[ 1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 4s^2 \ 3d^{10} \ 4p^6 \ 5s^2 \ 4d^{10} \ 5p^5 \][/tex]
Now we add the number of electrons in each subshell:
- [tex]\(1s^2\)[/tex] contributes [tex]\(2\)[/tex] electrons.
- [tex]\(2s^2\)[/tex] contributes [tex]\(2\)[/tex] electrons.
- [tex]\(2p^6\)[/tex] contributes [tex]\(6\)[/tex] electrons.
- [tex]\(3s^2\)[/tex] contributes [tex]\(2\)[/tex] electrons.
- [tex]\(3p^6\)[/tex] contributes [tex]\(6\)[/tex] electrons.
- [tex]\(4s^2\)[/tex] contributes [tex]\(2\)[/tex] electrons.
- [tex]\(3d^{10}\)[/tex] contributes [tex]\(10\)[/tex] electrons.
- [tex]\(4p^6\)[/tex] contributes [tex]\(6\)[/tex] electrons.
- [tex]\(5s^2\)[/tex] contributes [tex]\(2\)[/tex] electrons.
- [tex]\(4d^{10}\)[/tex] contributes [tex]\(10\)[/tex] electrons.
- [tex]\(5p^5\)[/tex] contributes [tex]\(5\)[/tex] electrons.
Summing these values together:
[tex]\[ 2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 5 = 53 \][/tex]
The total number of electrons in the atom is [tex]\(53\)[/tex], which corresponds to the atomic number of the element.
According to the periodic table, the element with atomic number [tex]\(53\)[/tex] is iodine.
Therefore, the name of the element is:
iodine
