Answer :
To find [tex]\( f(c) \)[/tex] using synthetic substitution for [tex]\( f(x) = 5x^5 + 10x^4 + 3x^3 + 8x^2 - 6x - 3 \)[/tex] and [tex]\( c = 3 \)[/tex], follow these steps:
1. List the coefficients of the polynomial:
[tex]\[ 5, \quad 10, \quad 3, \quad 8, \quad -6, \quad -3 \][/tex]
2. Start with the leading coefficient:
Place [tex]\(5\)[/tex] as the initial value.
[tex]\[ \text{Initial:} \quad 5 \][/tex]
3. Multiply this value by [tex]\(c = 3\)[/tex] and add the next coefficient:
[tex]\[ 5 \times 3 + 10 = 15 + 10 = 25 \][/tex]
4. Repeat this process with the new result:
[tex]\[ 25 \times 3 + 3 = 75 + 3 = 78 \][/tex]
[tex]\[ 78 \times 3 + 8 = 234 + 8 = 242 \][/tex]
[tex]\[ 242 \times 3 - 6 = 726 - 6 = 720 \][/tex]
[tex]\[ 720 \times 3 - 3 = 2160 - 3 = 2157 \][/tex]
5. List out intermediate results for clarity:
[tex]\[ \begin{align*} 1.\ 5 \\ 2.\ 25 \\ 3.\ 78 \\ 4.\ 242 \\ 5.\ 720 \\ 6.\ 2157 \end{align*} \][/tex]
6. The final result [tex]\( f(c) = 2157 \)[/tex]:
Thus, the final value of the polynomial evaluated at [tex]\( c = 3 \)[/tex] is:
[tex]\[ f(3) = 2157 \][/tex]
Interpreting the intermediate results sequence:
[tex]\[ [5, 25, 78, 242, 720, 2157] \][/tex]
So, the final result from synthetic substitution is:
[tex]\[ f(3) = 2157 \][/tex]
1. List the coefficients of the polynomial:
[tex]\[ 5, \quad 10, \quad 3, \quad 8, \quad -6, \quad -3 \][/tex]
2. Start with the leading coefficient:
Place [tex]\(5\)[/tex] as the initial value.
[tex]\[ \text{Initial:} \quad 5 \][/tex]
3. Multiply this value by [tex]\(c = 3\)[/tex] and add the next coefficient:
[tex]\[ 5 \times 3 + 10 = 15 + 10 = 25 \][/tex]
4. Repeat this process with the new result:
[tex]\[ 25 \times 3 + 3 = 75 + 3 = 78 \][/tex]
[tex]\[ 78 \times 3 + 8 = 234 + 8 = 242 \][/tex]
[tex]\[ 242 \times 3 - 6 = 726 - 6 = 720 \][/tex]
[tex]\[ 720 \times 3 - 3 = 2160 - 3 = 2157 \][/tex]
5. List out intermediate results for clarity:
[tex]\[ \begin{align*} 1.\ 5 \\ 2.\ 25 \\ 3.\ 78 \\ 4.\ 242 \\ 5.\ 720 \\ 6.\ 2157 \end{align*} \][/tex]
6. The final result [tex]\( f(c) = 2157 \)[/tex]:
Thus, the final value of the polynomial evaluated at [tex]\( c = 3 \)[/tex] is:
[tex]\[ f(3) = 2157 \][/tex]
Interpreting the intermediate results sequence:
[tex]\[ [5, 25, 78, 242, 720, 2157] \][/tex]
So, the final result from synthetic substitution is:
[tex]\[ f(3) = 2157 \][/tex]