To find the total resistance in a series circuit with multiple resistors, you simply add up all the individual resistances.
In this case, we have 12 light bulbs, and each light bulb has a resistance of 1 ohm.
Step-by-step, the total resistance in a series circuit is calculated as follows:
1. Determine the resistance of one light bulb. Here, each light bulb has a resistance of 1 ohm.
2. Count the total number of light bulbs. In this problem, there are 12 light bulbs.
3. Add the resistances together since they are in series.
So, the total resistance [tex]\( R_{total} \)[/tex] is:
[tex]\[ R_{total} = 1 \text{ ohm} + 1 \text{ ohm} + 1 \text{ ohm} + ... + 1 \text{ ohm} \][/tex]
Since there are 12 light bulbs, this is the same as multiplying the resistance of one bulb by the total number of bulbs:
[tex]\[ R_{total} = 12 \times 1 \text{ ohm} \][/tex]
[tex]\[ R_{total} = 12 \text{ ohms} \][/tex]
Therefore, the total resistance in the series circuit is:
[tex]\[ \boxed{12 \text{ ohms}} \][/tex]
So, the correct answer is:
12 ohms
