Find [tex] \| v \| - \| w \| [/tex], if [tex] v = -2i + 3j [/tex] and [tex] w = 6i - 6j [/tex].

[tex] \| v \| - \| w \| = \square [/tex]

(Type an exact answer, using radicals as needed. Simplify your answer.)



Answer :

Sure! Let's start by defining the vectors [tex]\( v \)[/tex] and [tex]\( w \)[/tex]:

Vector [tex]\( v = -2i + 3j \)[/tex]

Vector [tex]\( w = 6i - 6j \)[/tex]

First, we need to find the magnitudes of each vector.

1. Magnitude of vector [tex]\( v \)[/tex]:
The formula for the magnitude of a vector [tex]\( ai + bj \)[/tex] is given by:
[tex]\[ \|v\| = \sqrt{a^2 + b^2} \][/tex]
For [tex]\( v = -2i + 3j \)[/tex]:
[tex]\[ \|v\| = \sqrt{(-2)^2 + 3^2} = \sqrt{4 + 9} = \sqrt{13} \][/tex]

2. Magnitude of vector [tex]\( w \)[/tex]:
For [tex]\( w = 6i - 6j \)[/tex]:
[tex]\[ \|w\| = \sqrt{6^2 + (-6)^2} = \sqrt{36 + 36} = \sqrt{72} = 6\sqrt{2} \][/tex]

Now we find the difference in magnitudes [tex]\( \|v\| - \|w\| \)[/tex]:
[tex]\[ \|v\| = \sqrt{13} \][/tex]
[tex]\[ \|w\| = 6\sqrt{2} \][/tex]
[tex]\[ \|v\| - \|w\| = \sqrt{13} - 6\sqrt{2} \][/tex]

Thus, the exact answer is:
[tex]\( \boxed{\sqrt{13} - 6\sqrt{2}} \)[/tex]