Plot the points [tex]\((-6, 8)\)[/tex] and [tex]\((-6, -3)\)[/tex] on the coordinate plane below.

What is the distance between these two points?

[tex]\(\quad\)[/tex] units



Answer :

To determine the distance between the two points [tex]\((-6, 8)\)[/tex] and [tex]\((-6, -3)\)[/tex], we follow these steps:

1. Identify the coordinates of the points:
- Point [tex]\(A\)[/tex] has coordinates [tex]\((-6, 8)\)[/tex]
- Point [tex]\(B\)[/tex] has coordinates [tex]\((-6, -3)\)[/tex]

2. Understand the relationship between these points:
Since both points share the same [tex]\(x\)[/tex]-coordinate ([tex]\(-6\)[/tex]), they lie on a vertical line. This simplifies the calculation, as we only need to consider the difference in the [tex]\(y\)[/tex]-coordinates.

3. Calculate the difference in [tex]\(y\)[/tex]-coordinates:
- The [tex]\(y\)[/tex]-coordinate of point [tex]\(A\)[/tex] is [tex]\(8\)[/tex]
- The [tex]\(y\)[/tex]-coordinate of point [tex]\(B\)[/tex] is [tex]\(-3\)[/tex]

The distance between the points can be calculated by finding the absolute difference between the [tex]\(y\)[/tex]-coordinates:
[tex]\[ \text{Distance} = \left|8 - (-3)\right| \][/tex]

4. Perform the subtraction and calculate the absolute value:
[tex]\[ \left|8 - (-3)\right| = \left|8 + 3\right| = \left|11\right| = 11 \][/tex]

Therefore, the distance between the points [tex]\((-6, 8)\)[/tex] and [tex]\((-6, -3)\)[/tex] is [tex]\(11\)[/tex] units.