A school is offering an ice cream party where students can get 1 scoop or 2 scoops, chocolate or vanilla, and in a cup or a bowl.

Assuming the choices are equally likely, what is the probability that someone gets vanilla in a bowl?

A. [tex]$\frac{1}{16}$[/tex]
B. [tex][tex]$\frac{1}{8}$[/tex][/tex]
C. [tex]$\frac{1}{4}$[/tex]
D. [tex]$\frac{1}{2}$[/tex]



Answer :

To find the probability that someone gets vanilla in a bowl, let’s analyze the problem step-by-step.

Firstly, we need to determine the total number of possible choices. Each student has three dimensions of choice:

1. The number of scoops: 1 scoop or 2 scoops (2 choices).
2. The flavor: chocolate or vanilla (2 choices).
3. The container: in a cup or in a bowl (2 choices).

To find the total number of choices, we multiply the number of options in each dimension:

[tex]\[ \text{Total number of choices} = 2 \text{ (scoops)} \times 2 \text{ (flavors)} \times 2 \text{ (containers)} = 8 \][/tex]

Now, we need to determine the number of favorable outcomes where students get vanilla in a bowl. Let's break it down:

1. The number of scoops: 1 scoop or 2 scoops (2 choices).
2. The flavor: vanilla (1 choice).
3. The container: in a bowl (1 choice).

So, the number of favorable outcomes is:

[tex]\[ \text{Number of favorable outcomes} = 2 \text{ (scoops)} \times 1 \text{ (flavor: vanilla)} \times 1 \text{ (container: bowl)} = 2 \][/tex]

Now, to find the probability, we divide the number of favorable outcomes by the total number of choices:

[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of choices}} = \frac{2}{8} = \frac{1}{4} \][/tex]

Thus, the probability that someone gets vanilla in a bowl is:

[tex]\[ \boxed{\frac{1}{4}} \][/tex]

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