Unit Overview
Step-by-Step
Sample Problem
Hints

Use synthetic division to divide the two polynomials:

[tex]\[ w + 6 \ \longdiv \ -4w^{4} - 26w^{3} - 12w^{2} - 3w - 36 \][/tex]

1. Is the divisor given in [tex]\((x - r)\)[/tex] form?
- Yes

2. How many terms are in the dividend?

3. Enter the quotient and remainder.



Answer :

We need to use synthetic division to divide the given polynomials:

[tex]\[ w + 6 \longdiv{-4w^4 - 26w^3 - 12w^2 - 3w - 36} \][/tex]

Firstly, confirm that the divisor is in the form [tex]\(w + c\)[/tex]. Here it is [tex]\(w + 6\)[/tex]. Notice that the corresponding root for this divisor is [tex]\(w = -6\)[/tex].

Next, write down the coefficients of the dividend polynomial:

[tex]\[ -4, -26, -12, -3, -36 \][/tex]

Here’s a step-by-step procedure for synthetic division:

1. Write down the root of the divisor, which is -6.
2. Set up the synthetic division using the coefficients of the dividend and the root of the divisor.

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ \end{array} \][/tex]

3. Bring down the leading coefficient, -4, directly below the line:

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ & & -4 & & & \\ \end{array} \][/tex]

4. Multiply -4 (the number just brought down) by the root (-6), and write the result below the next coefficient in the dividend.

[tex]\[ -4 \times -6 = 24 \][/tex]

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ & & -4 & 24 & & \\ \end{array} \][/tex]

5. Add this result (24) to the next coefficient (-26):

[tex]\[ -26 + 24 = -2 \][/tex]

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ & & -4 & 24 & -2 & \\ \end{array} \][/tex]

6. Repeat this process for each of the remaining coefficients:

[tex]\[ -2 \times -6 = 12 \][/tex]

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ & & -4 & 24 & -2 & 12 \\ \end{array} \][/tex]

[tex]\[ -12 + 12 = 0 \][/tex]

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ & & -4 & 24 & -2 & 12 & 0 \\ \end{array} \][/tex]

[tex]\[ 0 \times -6 = 0 \][/tex]

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ & & -4 & 24 & -2 & 12 & 0 \\ \end{array} \][/tex]

[tex]\[ -3 + 0 = -3 \][/tex]

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ & & -4 & 24 & -2 & 12 & 0 & -3 \\ \end{array} \][/tex]

[tex]\[ -3 \times -6 = 18 \][/tex]

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ & & -4 & 24 & -2 & 12 & 0 & -3 & 18\\ \end{array} \][/tex]

[tex]\[ -36 + 18 = -18 \][/tex]

[tex]\[ \begin{array}{r|rrrrr} -6 & -4 & -26 & -12 & -3 & -36 \\ & & -4 & 24 & -2 & 12 & 0 & -3 & 18 & -18\\ \end{array} \][/tex]

The coefficients for the quotient polynomial are the numbers we get in the row after the line excluding the last number which is our remainder.

So, the quotient is:

[tex]\[ -4w^3 - 2w^2 + 0w - 3 \][/tex]

And the remainder is:

[tex]\[ -18 \][/tex]

Thus, the quotient and remainder of the division are:

[tex]\[ \boxed{(-4w^3 - 2w^2 + 0w - 3)} \][/tex]
[tex]\[ \boxed{-18} \][/tex]