To solve this single displacement reaction, we need to identify the products formed when Chlorine (Cl[tex]\(_2\)[/tex]) reacts with Sodium Bromide (NaBr).
1. This reaction is a single displacement reaction in which Chlorine (Cl[tex]\(_2\)[/tex]) will replace Bromine (Br) in Sodium Bromide (NaBr).
2. As a result of the reaction, Sodium Chloride (NaCl) and Bromine (Br[tex]\(_2\)[/tex]) are formed.
3. The balanced chemical equation is:
[tex]\[
2 \text{NaBr} + \text{Cl}_2 \rightarrow 2 \text{NaCl} + \text{Br}_2
\][/tex]
Let’s fill in the boxes in the chemical equation:
[tex]\[
2 \text{NaBr} + \text{Cl}_2 \rightarrow 2 \text{NaCl} + \text{Br}_2
\][/tex]
So, the correct chemical symbols to complete the equation are:
1. NaCl
2. Br[tex]\(_2\)[/tex]
In the boxes, you should write:
1. NaCl
2. Br[tex]\(_2\)[/tex]
Thus, the completed equation looks like:
[tex]\[ 2 \text{NaBr} + \text{Cl}_2 \rightarrow 2 \text{NaCl} + \text{Br}_2 \][/tex]
