The function [tex]$f(x)=\frac{200}{x}+10$[/tex] models the cost per student of a field trip when [tex]$x$[/tex] students go on the trip. How is the parent function [tex]$f(x)=\frac{1}{x}$[/tex] transformed to create the function [tex][tex]$f(x)=\frac{200}{x}+10$[/tex][/tex]?

A. It is vertically stretched by a factor of 200.
B. It is vertically stretched by a factor of 200 and shifted 10 units left.
C. It is vertically stretched by a factor of 200 and shifted 10 units up.
D. It is vertically stretched by a factor of 200 and shifted 10 units right.



Answer :

To understand how the parent function [tex]\( f(x) = \frac{1}{x} \)[/tex] is transformed to create the function [tex]\( f(x) = \frac{200}{x} + 10 \)[/tex], let's analyze each transformation step by step.

1. Vertical Stretch by a Factor of 200:
- The original function is [tex]\( f(x) = \frac{1}{x} \)[/tex].
- When we multiply the function by 200, we get [tex]\( f(x) = \frac{200}{x} \)[/tex].
- This transformation stretches the function vertically by a factor of 200.

2. Vertical Shift Up by 10 Units:
- After the vertical stretch, we have the function [tex]\( f(x) = \frac{200}{x} \)[/tex].
- Adding 10 to this function shifts it vertically upward by 10 units.
- Therefore, the new function becomes [tex]\( f(x) = \frac{200}{x} + 10 \)[/tex].

Combining these transformations:

- First, the function [tex]\( f(x) = \frac{1}{x} \)[/tex] is vertically stretched by a factor of 200.
- Then, the function [tex]\( f(x) = \frac{200}{x} \)[/tex] is shifted 10 units up.

The correct description of the transformations is:

It is vertically stretched by a factor of 200 and shifted 10 units up.

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