A refrigerating machine working on a reversed Carnot cycle takes out 2 kW of heat from the system while between temperature limits of 300 K and 200 K. Find COP and power consumed by the cycle will be respectively.

Given that, A refrigerating machine working on a reversed Carnot cycle takes out 2 kW of heat from the system while between temperature limits of 300 K and 200 K.

COP (Coefficient of Performance) :

To calculate the Coefficient of Performance, we'll use the formula:

[tex] \rm COP = \dfrac{T_2}{T_1 - T_2}[/tex]

here, [tex]\rm T_1 [/tex] & [tex]\rm T_2 [/tex] are the higher & lower temperatures.

For the given question,

[tex]\rm T_1 [/tex] = 300 K

[tex]\rm T_2 [/tex] = 200 K

Now, let's calculate the COP:

[tex]\rm COP = \dfrac{200}{300 - 200} \\ \\ \rm \: \: \: = \dfrac{200}{100} \\ \\ = 2 [/tex]

Hence, the Coefficient of Performance is 2.

Power consumed by the cycle :

We can calculate the power consumed by the cycle by using the formula:

[tex]\rm Power = \dfrac{Heat \ removed}{COP}[/tex]

Substitute the given values,

[tex] \rm Power = \dfrac{2}{2} [/tex]

[tex] \: \: \ \ \ \ \ \ = \rm 1 \ kW[/tex]

Therefore, The power consumed by the cycle will be 1 kW.