Solve the inequality.

[tex]\[
|4x - 7| \ \textgreater \ 3
\][/tex]

[tex]\[
x \ \textless \ [?] \text{ or } x \ \textgreater \ [?]
\][/tex]



Answer :

Certainly! To solve the inequality [tex]\( |4x - 7| > 3 \)[/tex], we need to analyze the inequality by considering the definition of absolute value.

The absolute value inequality [tex]\( |A| > B \)[/tex] (where [tex]\( B \)[/tex] is a positive number) can be split into two separate inequalities:

[tex]\[ A > B \quad \text{or} \quad A < -B \][/tex]

In this case, [tex]\( A = 4x - 7 \)[/tex] and [tex]\( B = 3 \)[/tex]. Therefore, we split the inequality [tex]\( |4x - 7| > 3 \)[/tex] into:

[tex]\[ 4x - 7 > 3 \quad \text{or} \quad 4x - 7 < -3 \][/tex]

Now, let's solve each inequality separately.

### Solving [tex]\( 4x - 7 > 3 \)[/tex]:

1. Add 7 to both sides to isolate the term with [tex]\( x \)[/tex]:
[tex]\[ 4x - 7 + 7 > 3 + 7 \][/tex]
Simplifying, we get:
[tex]\[ 4x > 10 \][/tex]

2. Divide both sides by 4 to solve for [tex]\( x \)[/tex]:
[tex]\[ x > \frac{10}{4} \][/tex]
Simplify the fraction:
[tex]\[ x > 2.5 \][/tex]

### Solving [tex]\( 4x - 7 < -3 \)[/tex]:

1. Add 7 to both sides:
[tex]\[ 4x - 7 + 7 < -3 + 7 \][/tex]
Simplifying, we get:
[tex]\[ 4x < 4 \][/tex]

2. Divide both sides by 4 to solve for [tex]\( x \)[/tex]:
[tex]\[ x < \frac{4}{4} \][/tex]
Simplify the fraction:
[tex]\[ x < 1 \][/tex]

### Combining the results

The solution to the inequality [tex]\( |4x - 7| > 3 \)[/tex] is the union of the two separate inequalities. Therefore, the complete solution is:

[tex]\[ x < 1 \quad \text{or} \quad x > 2.5 \][/tex]

So, in the inequality form:
[tex]\[ x < 1 \quad \text{or} \quad x > 2.5 \][/tex]

Thus, the values of [tex]\( x \)[/tex] that satisfy the original inequality are those where [tex]\( x \)[/tex] is less than 1 or greater than 2.5.

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