An observer [tex]\( (O) \)[/tex] spots a bird flying at a [tex]\( 35^{\circ} \)[/tex] angle from a line drawn horizontal to its nest. If the distance from the observer (O) to the bird (B) is 21,000 feet, how far is the bird (B) from its nest?

A. 12,045 feet
B. 14,704 feet
C. 16,980 feet
D. 17,202 feet



Answer :

To determine how far the bird (B) is from its nest (N), we'll consider the given problem using trigonometric principles.

1. Understand the given values:
- The angle of elevation from the observer (O) to the bird (B) is [tex]\(35^{\circ}\)[/tex].
- The distance from the observer (O) to the bird (B) is 21,000 feet.

2. Visualization:
Let's visualize this problem with a right-angled triangle:
- The hypotenuse of the triangle (OB) is the distance from the observer to the bird, which is 21,000 feet.
- The angle at O is [tex]\(35^{\circ}\)[/tex].
- We need to find the horizontal distance (BN) from the bird to the nest.

3. Relevant Trigonometric Function:
To find the horizontal distance, we need to use the cosine function, as cosine relates the adjacent side to the hypotenuse in a right-angled triangle:
[tex]\[ \cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}} \][/tex]
Here, the adjacent side is BN, the angle is [tex]\(35^{\circ}\)[/tex], and the hypotenuse is OB (21,000 feet).

4. Set up the equation:
[tex]\[ \cos(35^{\circ}) = \frac{BN}{21,000} \][/tex]

5. Solve for BN:
[tex]\[ BN = 21,000 \times \cos(35^{\circ}) \][/tex]

6. Use the cosine value:
Calculate [tex]\( \cos(35^{\circ}) \)[/tex] which is approximately 0.8192.

7. Multiply to find BN:
[tex]\[ BN = 21,000 \times 0.8192 = 17,202 \text{ feet} \][/tex]

Therefore, the horizontal distance from the bird to the nest is 17,202 feet. The correct answer is:
- 17,202 feet