For the polynomial below, [tex]\(-2\)[/tex] is a zero of multiplicity two.

[tex]\[ f(x) = x^4 + x^2 + 36x^4 + 52 \][/tex]

Express [tex]\( f(x) \)[/tex] as a product of linear factors.

[tex]\[ f(x) = \][/tex]



Answer :

To solve the given polynomial [tex]\( f(x) = x^4 + x^2 + 36x^4 + 52 \)[/tex] and express it as a product of linear factors, we'll follow these steps:

1. Combine Like Terms:
First, we combine the like terms in the given polynomial:
[tex]\[ f(x) = x^4 + x^2 + 36x^4 + 52 \][/tex]
[tex]\[ f(x) = (1x^4 + 36x^4) + x^2 + 52 \][/tex]
[tex]\[ f(x) = 37x^4 + x^2 + 52 \][/tex]

2. Factor the Polynomial:
Now, we need to factor the simplified polynomial [tex]\( 37x^4 + x^2 + 52 \)[/tex].

Since the polynomial [tex]\(37x^4 + x^2 + 52\)[/tex] involves higher-order terms and constants, we generally look for patterns or specific factorization techniques. Given in the problem, -2 is a zero of multiplicity two, we know that [tex]\( (x + 2)^2 \)[/tex] is a factor. However, for a polynomial of the degree 4, there are multiple ways to factorize.

Considering the factorization given, the polynomial doesn't break down into a simple product of linear factors. Instead, we'll state it in the implicitly factored form involving all terms.

3. State the Final Product:
Given the complex nature of this polynomial and knowing its solution doesn't yield distinct simple linear factors, our final expression remains:

[tex]\[ f(x) = 37x^4 + x^2 + 52 \][/tex]

Thus, due to the unique factorization property, our polynomial remains as a product involving the entire polynomial expression, considering its given complexities.

However, if simplified further with any roots calculations and intermediary algebraic steps, it could potentially translate into an elaborate form combining linear and quadratic factors, but in this exact given case:

[tex]\[ f(x) = \boxed{37x^4 + x^2 + 52} \][/tex]