Answer :
Let's solve the problem step-by-step.
### Problem Statement:
The sum of two numbers is 36. One number is 3 times as large as the other. We need to find these two numbers.
### Steps to Solve:
1. Define Variables:
Let's denote the smaller number as [tex]\( x \)[/tex].
2. Express the Larger Number:
Since one number is 3 times as large as the other, the larger number will be [tex]\( 3x \)[/tex].
3. Formulate the Equation:
According to the problem, the sum of the two numbers is 36. Therefore:
[tex]\[ x + 3x = 36 \][/tex]
4. Simplify the Equation:
Combine like terms:
[tex]\[ 4x = 36 \][/tex]
5. Solve for [tex]\( x \)[/tex]:
Divide both sides of the equation by 4 to find [tex]\( x \)[/tex]:
[tex]\[ x = \frac{36}{4} = 9 \][/tex]
6. Find the Larger Number:
Since the larger number is 3 times the smaller number:
[tex]\[ 3x = 3 \times 9 = 27 \][/tex]
### Final Answer:
The larger number is 27 and the smaller number is 9.
### Problem Statement:
The sum of two numbers is 36. One number is 3 times as large as the other. We need to find these two numbers.
### Steps to Solve:
1. Define Variables:
Let's denote the smaller number as [tex]\( x \)[/tex].
2. Express the Larger Number:
Since one number is 3 times as large as the other, the larger number will be [tex]\( 3x \)[/tex].
3. Formulate the Equation:
According to the problem, the sum of the two numbers is 36. Therefore:
[tex]\[ x + 3x = 36 \][/tex]
4. Simplify the Equation:
Combine like terms:
[tex]\[ 4x = 36 \][/tex]
5. Solve for [tex]\( x \)[/tex]:
Divide both sides of the equation by 4 to find [tex]\( x \)[/tex]:
[tex]\[ x = \frac{36}{4} = 9 \][/tex]
6. Find the Larger Number:
Since the larger number is 3 times the smaller number:
[tex]\[ 3x = 3 \times 9 = 27 \][/tex]
### Final Answer:
The larger number is 27 and the smaller number is 9.