To solve the system of linear equations [tex]3x + 5y = 2[/tex] and [tex]6x + 10y = 8[/tex] by using the linear combination method, Laura correctly multiplied the first equation by -2 to get [tex]-6x - 10y = -4[/tex] and then correctly added the equations [tex]-6x - 10y = -4[/tex] and [tex]6x + 10y = 8[/tex] to get [tex]0 = 4[/tex]. How many solutions are there to the system of equations?

A. 0
B. 1
C. 2
D. 4



Answer :

To solve the given system of equations using the linear combination (or addition) method, let's analyze the steps involved:

We start with the system of equations:
1. [tex]\( 3x + 5y = 2 \)[/tex]
2. [tex]\( 6x + 10y = 8 \)[/tex]

Laura correctly multiplies the first equation by -2:
[tex]\[ -2 \times (3x + 5y) = -2 \times 2 \][/tex]
This simplifies to:
[tex]\[ -6x - 10y = -4 \][/tex]

Next, she adds the modified first equation to the second equation:
[tex]\[ (-6x - 10y) + (6x + 10y) = -4 + 8 \][/tex]

Combining the left-hand side terms:
[tex]\[ -6x - 10y + 6x + 10y = 0 \][/tex]
This simplifies to:
[tex]\[ 0 = -4 + 8 \][/tex]

And combining the right-hand sides:
[tex]\[ 0 = 4 \][/tex]

The resulting equation [tex]\( 0 = 4 \)[/tex] is a contradiction, as [tex]\( 0 \)[/tex] cannot equal [tex]\( 4 \)[/tex].

Since we arrived at a contradiction, this means that the system of equations is inconsistent and has no solutions.

Thus, the number of solutions to the system of equations is:
[tex]\[ 0 \][/tex]