To determine the volume of aluminum given its mass and density, we can use the formula relating mass, density, and volume:
[tex]\[ \text{volume} = \frac{\text{mass}}{\text{density}} \][/tex]
We are given:
- The density of aluminum ([tex]\(\rho\)[/tex]) as 270 kg/m³
- The mass of the aluminum (m) as 49.9 kg
Substitute these values into the formula to find the volume:
[tex]\[ \text{volume} = \frac{49.9 \text{ kg}}{270 \text{ kg/m}^3} \][/tex]
When we perform the division:
[tex]\[ \text{volume} = 0.18481481481481482 \text{ m}^3 \][/tex]
Therefore, the volume of aluminum that would have a mass of 49.9 kg is approximately 0.1848 m³.
