Answer :
To determine the frequency of the recessive allele in a population, we need to consider the contribution of each genetic group (homozygous dominant, heterozygous dominant, and homozygous recessive) to the gene pool.
Here's a step-by-step breakdown:
1. Determine the total population:
- Homozygous dominant (AA): 45
- Heterozygous dominant (Aa): 30
- Homozygous recessive (aa): 25
- Total population = 45 (AA) + 30 (Aa) + 25 (aa) = 100
2. Count the total number of alleles in the population:
Each chicken has 2 alleles for the comb trait.
- Total alleles = Total population 2
- Total alleles = 100 2 = 200 alleles in the population
3. Count the total number of recessive alleles (a) present:
- Homozygous dominant (AA) individuals have 0 recessive alleles.
- Heterozygous dominant (Aa) individuals have 1 recessive allele each.
- Recessive alleles contributed by heterozygous dominant = 30 1 = 30
- Homozygous recessive (aa) individuals have 2 recessive alleles each.
- Recessive alleles contributed by homozygous recessive = 25 2 = 50
- Total recessive alleles = 30 (from Aa) + 50 (from aa) = 80
4. Calculate the frequency of the recessive allele (a):
The frequency of the recessive allele is the number of recessive alleles divided by the total number of alleles.
- Frequency of the recessive allele (a) = Total recessive alleles / Total alleles
- Frequency of the recessive allele = 80 / 200 = 0.4 or 40%
Thus, the correct expression to calculate the frequency of the recessive allele in the population is
[tex]\[ \frac{80}{200} \][/tex]
So, the correct answer is:
[tex]\[ \boxed{\text{B. } \frac{80}{200}} \][/tex]
Here's a step-by-step breakdown:
1. Determine the total population:
- Homozygous dominant (AA): 45
- Heterozygous dominant (Aa): 30
- Homozygous recessive (aa): 25
- Total population = 45 (AA) + 30 (Aa) + 25 (aa) = 100
2. Count the total number of alleles in the population:
Each chicken has 2 alleles for the comb trait.
- Total alleles = Total population 2
- Total alleles = 100 2 = 200 alleles in the population
3. Count the total number of recessive alleles (a) present:
- Homozygous dominant (AA) individuals have 0 recessive alleles.
- Heterozygous dominant (Aa) individuals have 1 recessive allele each.
- Recessive alleles contributed by heterozygous dominant = 30 1 = 30
- Homozygous recessive (aa) individuals have 2 recessive alleles each.
- Recessive alleles contributed by homozygous recessive = 25 2 = 50
- Total recessive alleles = 30 (from Aa) + 50 (from aa) = 80
4. Calculate the frequency of the recessive allele (a):
The frequency of the recessive allele is the number of recessive alleles divided by the total number of alleles.
- Frequency of the recessive allele (a) = Total recessive alleles / Total alleles
- Frequency of the recessive allele = 80 / 200 = 0.4 or 40%
Thus, the correct expression to calculate the frequency of the recessive allele in the population is
[tex]\[ \frac{80}{200} \][/tex]
So, the correct answer is:
[tex]\[ \boxed{\text{B. } \frac{80}{200}} \][/tex]