Predict the general term, or nth term, [tex]a_n[/tex], of the sequence.

[tex]\[
-10, 50, -250, 1250, -6250, \ldots
\][/tex]

[tex]\[
a_n = \square
\][/tex]

(Simplify your answer.)



Answer :

To determine the general term [tex]\(a_n\)[/tex] of the sequence [tex]\(-10, 50, -250, 1250, -6250, \ldots\)[/tex], we will follow these steps:

1. Identify the first term [tex]\((a_1)\)[/tex]:
The first term of the sequence is [tex]\(a_1 = -10\)[/tex].

2. Determine the common ratio [tex]\((r)\)[/tex]:
To find the common ratio, divide the second term by the first term:
[tex]\[ r = \frac{50}{-10} = -5 \][/tex]
Verify the common ratio with the next terms:
[tex]\[ \frac{-250}{50} = -5 \quad \text{and} \quad \frac{1250}{-250} = -5 \][/tex]
The common ratio [tex]\(r\)[/tex] is consistently [tex]\(-5\)[/tex].

3. Formulate the general term for a geometric sequence:
The general formula for the nth term of a geometric sequence is given by:
[tex]\[ a_n = a_1 \cdot r^{(n-1)} \][/tex]
Plugging in the values for [tex]\(a_1\)[/tex] and [tex]\(r\)[/tex]:
[tex]\[ a_n = -10 \cdot (-5)^{(n-1)} \][/tex]
This provides the simplified general term of the sequence.

Therefore, the general term [tex]\(a_n\)[/tex] of the given sequence is:
[tex]\[ a_n = -10 \cdot (-5)^{(n-1)} \][/tex]