Let's break down the problem into parts and solve each one step by step.
### Given:
- Boy [tex]\(a\)[/tex] is pulling with a force of [tex]\(2 \, \text{N}\)[/tex] to the left.
- Boy [tex]\(b\)[/tex] is pulling with a force of [tex]\(5 \, \text{N}\)[/tex] to the right.
### A. What will be the net force on the cabinet?
The net force on the cabinet is the difference between the forces exerted by boy [tex]\(a\)[/tex] and boy [tex]\(b\)[/tex]. Since the forces are in opposite directions, you subtract the smaller force from the larger force:
[tex]\[ \text{Net Force} = 5 \, \text{N} - 2 \, \text{N} = 3 \, \text{N} \][/tex]
### B. Will the cabinet move?
For an object to move, there must be a net force acting on it. In this case, the net force is [tex]\(3 \, \text{N}\)[/tex] which is not zero. Therefore, the cabinet will move.
### C. To what direction will it move?
The direction of movement is determined by the direction of the larger force. Since boy [tex]\(b\)[/tex] is exerting a larger force ([tex]\(5 \, \text{N}\)[/tex] to the right) than boy [tex]\(a\)[/tex] ([tex]\(2 \, \text{N}\)[/tex] to the left), the cabinet will move to the right.
### Summary:
- Net Force: [tex]\(3 \, \text{N}\)[/tex]
- Will the cabinet move: Yes, it will move.
- Direction of movement: To the right
