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What is the solution of this equation?

[tex]\[ -\frac{1}{2} n^2 + 18 = 0 \][/tex]

[tex]\[ n = \pm \square \][/tex]



Answer :

To solve the equation [tex]\(-\frac{1}{2} n^2 + 18 = 0\)[/tex], we need to find the values of [tex]\( n \)[/tex] that satisfy this equation. Here is a step-by-step process to solve it:

1. Start with the given equation:
[tex]\[ -\frac{1}{2} n^2 + 18 = 0 \][/tex]

2. To eliminate the fraction, multiply every term by [tex]\(-2\)[/tex] to simplify:
[tex]\[ n^2 - 36 = 0 \][/tex]

3. Rewrite the equation to isolate the [tex]\( n^2 \)[/tex] term:
[tex]\[ n^2 = 36 \][/tex]

4. Solve for [tex]\( n \)[/tex] by taking the square root of both sides. Remember that the square root of a number can be both positive and negative:
[tex]\[ n = \pm \sqrt{36} \][/tex]

5. Simplify the square root:
[tex]\[ \sqrt{36} = 6 \][/tex]

6. Therefore, the solutions to the equation are:
[tex]\[ n = \pm 6 \][/tex]

Thus, the solution of the equation is:
[tex]\[ n = \pm 6 \][/tex]