The function [tex]\( g \)[/tex] is defined by the following rule:

[tex]\[ g(x) = -x - 5 \][/tex]

Complete the function table.

[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $g(x)$ \\
\hline
-4 & $\square$ \\
\hline
-3 & $\square$ \\
\hline
0 & $\square$ \\
\hline
2 & $\square$ \\
\hline
5 & $\square$ \\
\hline
\end{tabular}
\][/tex]



Answer :

Let's complete the function table for the function [tex]\( g(x) = -x - 5 \)[/tex].

1. For [tex]\( x = -4 \)[/tex]:
[tex]\[ g(-4) = -(-4) - 5 = 4 - 5 = -1 \][/tex]
So, [tex]\( g(-4) = -1 \)[/tex].

2. For [tex]\( x = -3 \)[/tex]:
[tex]\[ g(-3) = -(-3) - 5 = 3 - 5 = -2 \][/tex]
So, [tex]\( g(-3) = -2 \)[/tex].

3. For [tex]\( x = 0 \)[/tex]:
[tex]\[ g(0) = -0 - 5 = -5 \][/tex]
So, [tex]\( g(0) = -5 \)[/tex].

4. For [tex]\( x = 2 \)[/tex]:
[tex]\[ g(2) = -2 - 5 = -7 \][/tex]
So, [tex]\( g(2) = -7 \)[/tex].

5. For [tex]\( x = 5 \)[/tex]:
[tex]\[ g(5) = -5 - 5 = -10 \][/tex]
So, [tex]\( g(5) = -10 \)[/tex].

Now, let's complete the table with these results.

[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $g(x)$ \\ \hline -4 & -1 \\ \hline -3 & -2 \\ \hline 0 & -5 \\ \hline 2 & -7 \\ \hline 5 & -10 \\ \hline \end{tabular} \][/tex]