Sure, let's analyze the valence electrons for each given element and then determine which two elements share the same number of valence electrons.
1. Barium (Atomic Number 56):
- The electron configuration for barium is [tex]\([Xe] 6s^2\)[/tex]. This means that the electrons are configured in such a way that barium has two electrons in its outermost shell, the 6s shell.
- Therefore, barium has 2 valence electrons.
2. Neon (Atomic Number 10):
- The electron configuration for neon is [tex]\([He] 2s^2 2p^6\)[/tex]. This means that neon has a complete outer shell with a total of eight electrons (2 from 2s and 6 from 2p).
- Therefore, neon has 8 valence electrons.
3. Silicon (Atomic Number 14):
- The electron configuration for silicon is [tex]\([Ne] 3s^2 3p^2\)[/tex]. This configuration shows that silicon has four electrons in its outermost shell (2 from 3s and 2 from 3p).
- Therefore, silicon has 4 valence electrons.
4. Carbon (Atomic Number 6):
- The electron configuration for carbon is [tex]\([He] 2s^2 2p^2\)[/tex]. This indicates that carbon also has four electrons in its outer shell (2 from 2s and 2 from 2p).
- Therefore, carbon has 4 valence electrons.
By comparing the number of valence electrons:
- Barium has 2 valence electrons.
- Neon has 8 valence electrons.
- Silicon has 4 valence electrons.
- Carbon has 4 valence electrons.
Thus, the two elements that have the same number of valence electrons are silicon and carbon.
Final selection:
- Silicon (Element with Atomic Number 14)
- Carbon (Element with Atomic Number 6)
