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A parabola is given by the equation [tex]y^2 = -24x[/tex].

The equation of the directrix of the parabola is [tex]\square[/tex].

The focus of the parabola is [tex]\square[/tex].



Answer :

To solve the problem, let's break it down step-by-step:

1. Identify the form of the given equation:
The given equation of the parabola is [tex]\( y^2 = -24x \)[/tex].

2. Rewrite the equation in the standard form:
The standard form of a parabola that opens left or right is [tex]\( y^2 = 4px \)[/tex]. By comparing this with the given equation [tex]\( y^2 = -24x \)[/tex], we can identify that [tex]\( 4p = -24 \)[/tex].

3. Solve for [tex]\( p \)[/tex]:
Dividing both sides by 4, we get:
[tex]\[ p = \frac{-24}{4} = -6 \][/tex]

4. Determine the equation of the directrix:
For a parabola in the form [tex]\( y^2 = 4px \)[/tex], the directrix is given by [tex]\( x = -p \)[/tex]. Substituting [tex]\( p = -6 \)[/tex], we get:
[tex]\[ \text{Directrix: } x = -(-6) = 6 \][/tex]

5. Determine the focus:
The focus of a parabola given by [tex]\( y^2 = 4px \)[/tex] is located at [tex]\( (p, 0) \)[/tex]. Substituting [tex]\( p = -6 \)[/tex], we get:
[tex]\[ \text{Focus: } (-6, 0) \][/tex]

So, the correct answers are:
- The equation of the directrix of the parabola is [tex]\( x = 6 \)[/tex].
- The focus of the parabola is [tex]\( (-6, 0) \)[/tex].