To find the weight/volume percentage concentration of isopropanol in the rubbing alcohol solution, follow these steps:
1. Determine the weight of the isopropanol:
- The weight of isopropanol given is [tex]\( 17.0 \)[/tex] grams.
2. Determine the volume of the solution:
- The total volume of the solution given is [tex]\( 20.0 \)[/tex] milliliters (mL).
3. Calculate the weight/volume percentage concentration:
- The weight/volume percentage concentration is calculated using the formula:
[tex]\[
\text{Weight/Volume \%} = \left(\frac{\text{Weight of Solute} (g)}{\text{Volume of Solution} (mL)}\right) \times 100
\][/tex]
- Plug in the given values:
[tex]\[
\text{Weight/Volume \%} = \left(\frac{17.0 \, \text{g}}{20.0 \, \text{mL}}\right) \times 100
\][/tex]
4. Perform the calculation:
- Calculating this gives:
[tex]\[
\frac{17.0}{20.0} = 0.85
\][/tex]
[tex]\[
0.85 \times 100 = 85.0
\][/tex]
Hence, the weight/volume percentage concentration of isopropanol in the solution is [tex]\( 85.0 \% \)[/tex].
Make sure to keep the correct number of significant figures, which in this case is three due to the given values [tex]\( 17.0 \, \text{g} \)[/tex] and [tex]\( 20.0 \, \text{mL} \)[/tex].
Part 1 of 2:
[tex]\[ 85.0 \% \left(\frac{\text{weight}}{\text{volume}}\right) \text{isopropanol} \][/tex]
