Answer :
To classify the given system of linear equations:
[tex]\[ \left\{\begin{array}{l} x - 2y = 4 \\ y = \frac{1}{2}x + 6 \end{array}\right. \][/tex]
Let's go through a detailed, step-by-step process.
1. Rewrite the second equation in the standard form:
The first equation is already in the standard form:
[tex]\[ x - 2y = 4 \][/tex]
The second equation given is:
[tex]\[ y = \frac{1}{2}x + 6 \][/tex]
Multiply both sides of the second equation by 2 to clear the fraction:
[tex]\[ 2y = x + 12 \][/tex]
Now, let's rewrite it in the standard form:
[tex]\[ x - 2y = -12 \][/tex]
2. Compare the two equations:
Now we have:
[tex]\[ \left\{\begin{array}{l} x - 2y = 4 \\ x - 2y = -12 \end{array}\right. \][/tex]
We can see that the left-hand sides of both equations are identical, but the right-hand sides are different.
3. Analyze the equations:
Both equations have the same left-hand side, [tex]\( x - 2y \)[/tex].
This means they are parallel lines with no points in common, as their right-hand sides are different (4 and -12).
Consequently, the system of equations has no solution because parallel lines do not intersect.
Such a system is classified as inconsistent.
Thus, the classification that describes the system of linear equations is:
[tex]\[ \boxed{\text{inconsistent}} \][/tex]
[tex]\[ \left\{\begin{array}{l} x - 2y = 4 \\ y = \frac{1}{2}x + 6 \end{array}\right. \][/tex]
Let's go through a detailed, step-by-step process.
1. Rewrite the second equation in the standard form:
The first equation is already in the standard form:
[tex]\[ x - 2y = 4 \][/tex]
The second equation given is:
[tex]\[ y = \frac{1}{2}x + 6 \][/tex]
Multiply both sides of the second equation by 2 to clear the fraction:
[tex]\[ 2y = x + 12 \][/tex]
Now, let's rewrite it in the standard form:
[tex]\[ x - 2y = -12 \][/tex]
2. Compare the two equations:
Now we have:
[tex]\[ \left\{\begin{array}{l} x - 2y = 4 \\ x - 2y = -12 \end{array}\right. \][/tex]
We can see that the left-hand sides of both equations are identical, but the right-hand sides are different.
3. Analyze the equations:
Both equations have the same left-hand side, [tex]\( x - 2y \)[/tex].
This means they are parallel lines with no points in common, as their right-hand sides are different (4 and -12).
Consequently, the system of equations has no solution because parallel lines do not intersect.
Such a system is classified as inconsistent.
Thus, the classification that describes the system of linear equations is:
[tex]\[ \boxed{\text{inconsistent}} \][/tex]