Which classification describes the system of linear equations?

[tex]\[
\left\{\begin{array}{l}
x - 2y = 4 \\
y = \frac{1}{2}x + 6
\end{array}\right.
\][/tex]

A. Consistent dependent
B. Consistent independent
C. Inconsistent



Answer :

To classify the given system of linear equations:
[tex]\[ \left\{\begin{array}{l} x - 2y = 4 \\ y = \frac{1}{2}x + 6 \end{array}\right. \][/tex]

Let's go through a detailed, step-by-step process.

1. Rewrite the second equation in the standard form:

The first equation is already in the standard form:
[tex]\[ x - 2y = 4 \][/tex]

The second equation given is:
[tex]\[ y = \frac{1}{2}x + 6 \][/tex]

Multiply both sides of the second equation by 2 to clear the fraction:
[tex]\[ 2y = x + 12 \][/tex]

Now, let's rewrite it in the standard form:
[tex]\[ x - 2y = -12 \][/tex]

2. Compare the two equations:

Now we have:
[tex]\[ \left\{\begin{array}{l} x - 2y = 4 \\ x - 2y = -12 \end{array}\right. \][/tex]

We can see that the left-hand sides of both equations are identical, but the right-hand sides are different.

3. Analyze the equations:

Both equations have the same left-hand side, [tex]\( x - 2y \)[/tex].
This means they are parallel lines with no points in common, as their right-hand sides are different (4 and -12).

Consequently, the system of equations has no solution because parallel lines do not intersect.

Such a system is classified as inconsistent.

Thus, the classification that describes the system of linear equations is:

[tex]\[ \boxed{\text{inconsistent}} \][/tex]