[tex]$\$[/tex]10,000[tex]$ is borrowed at an interest rate of $[/tex]6\%[tex]$ per year. It will be paid back in 10 equal yearly installments. The formula for the periodic payment $[/tex]P[tex]$ can be determined by solving the following equation:

\[
10000 = \frac{P}{(1+0.06)} + \frac{P}{(1+0.06)^2} + \frac{P}{(1+0.06)^3} + \cdots + \frac{P}{(1+0.06)^{10}}
\]

Which of the following statements is correct?

A. The series is geometric with a common ratio of $[/tex]1.06[tex]$

B. The series is arithmetic with a common ratio of $[/tex]\frac{1}{1.06}[tex]$

C. The series is geometric with a common ratio of $[/tex]\frac{1}{1.06}[tex]$

D. The series is arithmetic with a common ratio of $[/tex]1.06$



Answer :

To solve the given problem, we need to identify the nature of the series and determine the correct common ratio.

Given series:
[tex]\[ 10000 = \frac{P}{(1+0.04)} + \frac{P}{(1+0.04)^2} + \frac{P}{(1+0.04)^3} + \cdots + \frac{P}{(1+0.04)^{10}} \][/tex]

Let's analyze the structure of this series:

1. Nature of the Series:
- Each term in the series can be described as [tex]\(\frac{P}{(1+0.04)^n}\)[/tex] where [tex]\(n\)[/tex] is the term number (ranging from 1 to 10).
- Notice that each term after the first is obtained by multiplying the previous term by a common ratio [tex]\(\frac{1}{(1+0.04)}\)[/tex].

2. Common Ratio:
- To identify the common ratio, take the ratio of the second term to the first term:
[tex]\[ \frac{\frac{P}{(1+0.04)^2}}{\frac{P}{(1+0.04)}} = \frac{1}{(1+0.04)} \][/tex]
- Simplifying further:
[tex]\[ \text{Common ratio} = \frac{1}{1.04} \][/tex]

Given that [tex]\(\frac{1}{1.04}\)[/tex] simplifies numerically to approximately [tex]\(0.9615384615384615\)[/tex], we can conclude that:

- The series is geometric.
- The common ratio of the series is [tex]\(\frac{1}{1.04}\)[/tex].

Hence, among the given choices, the correct statement is:
- The series is geometric with a common ratio of [tex]\(\frac{1}{1.04}\)[/tex].