Marco picked [tex]$8 \frac{1}{2}$[/tex] pounds of apples at an orchard last weekend. He used [tex]$\frac{1}{4}$[/tex] of the apples to make a pie for a party. Then, he used [tex][tex]$3 \frac{1}{8}$[/tex][/tex] pounds of apples to make applesauce. How many pounds of apples does Marco have left?

Write your answer as a whole number, fraction, or mixed number. Simplify any fractions.

[tex]\square[/tex] pounds



Answer :

Let's solve the problem step by step.

1. Initial amount of apples:
Marco initially picked [tex]\(8 \frac{1}{2}\)[/tex] pounds of apples.

We can convert [tex]\(8 \frac{1}{2}\)[/tex] to an improper fraction:
[tex]\[ 8 \frac{1}{2} = 8 + \frac{1}{2} = \frac{16}{2} + \frac{1}{2} = \frac{17}{2} \][/tex]

2. Apples used to make a pie:
Marco used [tex]\(\frac{1}{4}\)[/tex] of the apples to make a pie. To find this amount:
[tex]\[ \frac{1}{4} \times \frac{17}{2} = \frac{17}{8} \][/tex]
So, [tex]\( \frac{17}{8} \)[/tex] pounds of apples were used for the pie.

3. Apples used to make applesauce:
Marco then used [tex]\(3 \frac{1}{8}\)[/tex] pounds of apples to make applesauce.

We convert [tex]\(3 \frac{1}{8}\)[/tex] to an improper fraction:
[tex]\[ 3 \frac{1}{8} = 3 + \frac{1}{8} = \frac{24}{8} + \frac{1}{8} = \frac{25}{8} \][/tex]

Here, [tex]\(3 \frac{1}{8}\)[/tex] is equivalent to [tex]\( \frac{25}{8} \)[/tex] pounds.

4. Total apples used:
Now, let's calculate the total amount of apples used by adding both quantities:
[tex]\[ \frac{17}{8} + \frac{25}{8} = \frac{17 + 25}{8} = \frac{42}{8} \][/tex]

Simplifying [tex]\( \frac{42}{8} \)[/tex] by dividing both the numerator and the denominator by their greatest common divisor (2):
[tex]\[ \frac{42}{8} = \frac{21}{4} \][/tex]

5. Amount of apples left:
Finally, we subtract the amount of apples used from the initial amount to find out how many pounds of apples Marco has left:
[tex]\[ \frac{17}{2} - \frac{21}{4} \][/tex]

To perform this subtraction, we need a common denominator for the fractions. The least common multiple of 2 and 4 is 4. Convert [tex]\( \frac{17}{2} \)[/tex] to a fraction with a denominator of 4:
[tex]\[ \frac{17}{2} = \frac{34}{4} \][/tex]

Now the subtraction:
[tex]\[ \frac{34}{4} - \frac{21}{4} = \frac{34 - 21}{4} = \frac{13}{4} \][/tex]

Convert [tex]\( \frac{13}{4} \)[/tex] to a mixed number:
[tex]\[ \frac{13}{4} = 3 \frac{1}{4} \][/tex]

Therefore, Marco has [tex]\(3 \frac{1}{4}\)[/tex] pounds of apples left. So the answer is:

[tex]\[ \boxed{3 \frac{1}{4}} \][/tex]