What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures [tex]90^{\circ}[/tex]?

A. [tex]360^{\circ}[/tex]
B. [tex]1080^{\circ}[/tex]
C. [tex]900^{\circ}[/tex]
D. [tex]720^{\circ}[/tex]
E. [tex]180^{\circ}[/tex]
F. [tex]540^{\circ}[/tex]



Answer :

To determine the sum of the measures of the interior angles of a regular polygon where each exterior angle measures [tex]\(90^\circ\)[/tex], we can follow these steps:

1. Understand the relationship between exterior and interior angles:
- Each exterior angle of a regular polygon can be found by dividing the total sum of exterior angles, which is always [tex]\(360^\circ\)[/tex], by the number of sides (denoted as [tex]\(n\)[/tex]) the polygon has.
- Given that each exterior angle measures [tex]\(90^\circ\)[/tex], we can figure out the number of sides using the formula:
[tex]\[ \text{Exterior Angle} = \frac{360^\circ}{n} \][/tex]
[tex]\[ 90^\circ = \frac{360^\circ}{n} \][/tex]
- Solving for [tex]\(n\)[/tex]:
[tex]\[ n = \frac{360^\circ}{90^\circ} = 4 \][/tex]

2. Determine the sum of the interior angles of the polygon:
- The sum of the interior angles of a polygon is given by the formula:
[tex]\[ \text{Sum of Interior Angles} = (n-2) \times 180^\circ \][/tex]
- Substituting [tex]\(n = 4\)[/tex]:
[tex]\[ \text{Sum of Interior Angles} = (4-2) \times 180^\circ = 2 \times 180^\circ = 360^\circ \][/tex]

Therefore, the sum of the measures of the interior angles of the regular polygon is [tex]\(\boxed{360^\circ}\)[/tex].