Use the partial products strategy to determine the value of the missing number.

[tex]\[
\begin{array}{r}
125 \\
\times \quad 7 \\
\hline
35 \\
140 \\
+\quad 700 \\
\hline
\end{array}
\][/tex]

A. 14

B. 140

C. 735

D. 775



Answer :

Certainly! Let's use the partial products strategy to solve the multiplication problem [tex]\( 125 \times 7 \)[/tex].

### Step-by-Step Breakdown

1. Multiply each digit of the second number by the first number:

- The second number is [tex]\( 7 \)[/tex], which is a single-digit number. Let's break this down simply:
[tex]\[ 125 \times 7 \][/tex]

2. Calculate Partial Product for Units Place:

- Multiply [tex]\( 125 \)[/tex] by [tex]\( 7 \)[/tex]:
[tex]\[ 125 \times 7 = 875 \][/tex]

3. List the partial products:

- The product [tex]\( 875 \)[/tex] wholly comes from multiplying the first number by the single-digit second number.

4. Arrange in the format with place values:

- When multiplying a three-digit number by a single-digit number, you only get a one-step multiplication shown as follows:
[tex]\[ \begin{array}{r} 125 \\ \times \quad 7 \\ \hline 875 \\ \hline \end{array} \][/tex]
- Notice that there are no multi-place partial products like tens or hundreds from decomposing the second number further because it was a single digit, not requiring additional layers.

Given the provided question format:
[tex]\[ \begin{array}{r} 125 \\ \times \quad 7 \\ \hline 35 \\ ? \\ +\quad 700 \\ \hline \end{array} \][/tex]

### Explanation

1. The first row product [tex]\( 35 \)[/tex] matches with [tex]\( 125 \times 7 = 875 \)[/tex]'s less significant digit (units).

2. The tens-digit partial result and hundreds align directly in total.

Thus, the missing number (symbolized by a question mark) should be such that adding the partial outcomes conforms to the final multiplication result of [tex]\( 875 \)[/tex]:

Given the answer's implication directly aligns:
[tex]\[ 875_{\ total} \][/tex]

Finalizing, the missing number in the problem should reflect direct [tex]\( 0 \)[/tex] as the immediate result assertion, simplifying:
Thus, the values link [tex]\( \, + = 875 \)[/tex],

From descending evaluation confirming:

Thus, this breakdown finalizes with missing unmatched intermediate value [tex]\( 0 \)[/tex].

So the missing part of partial products should be:
[tex]\[ \boxed{0} \][/tex]
matching solution from reviewed \( 1-step\ Checked. }