Theo recorded the means and mean absolute deviations of his language arts and biology scores. He found the difference in the means of the scores of the two subjects. What is the approximate ratio of the difference in the means to each of the mean absolute deviations?

\begin{tabular}{|c|c|c|}
\hline
\multicolumn{3}{|c|}{Means and Mean Absolute Deviations of Theo's Scores} \\
\hline
& Language Arts & Biology \\
\hline
Mean & [tex]$98$[/tex] & [tex]$90$[/tex] \\
\hline
Mean Absolute Deviation & [tex]$2$[/tex] & [tex]$5$[/tex] \\
\hline
\end{tabular}

A. [tex]$18$[/tex]
B. [tex]$28$[/tex]



Answer :

Sure, let's break down the given problem step-by-step in solving it:

Step 1: Understanding the Data

Theo recorded the following data for his scores:
- Mean score for Language Arts: 98
- Mean score for Biology: 90
- Mean Absolute Deviation: 2

Step 2: Finding the Difference in the Means

To find the difference in the mean scores of Theo's Language Arts and Biology, we subtract the mean score of Biology from the mean score of Language Arts:
[tex]\[ \text{Difference in means} = \text{Mean score for Language Arts} - \text{Mean score for Biology} \][/tex]
Substituting the given values:
[tex]\[ \text{Difference in means} = 98 - 90 = 8 \][/tex]

Step 3: Calculating the Ratio

Next, we need to find the ratio of the difference in the means to the mean absolute deviation. The formula for the ratio is:
[tex]\[ \text{Ratio} = \frac{\text{Difference in means}}{\text{Mean absolute deviation}} \][/tex]
We substitute the values we have:
[tex]\[ \text{Ratio} = \frac{8}{2} = 4.0 \][/tex]

Summary:

- The difference in the means of Theo's scores in Language Arts and Biology is 8.
- The ratio of this difference to the mean absolute deviation is 4.0.

Therefore, the approximate ratio of the difference in the means to each of the mean absolute deviations is 4.0.