When a principal amount, [tex]$P$[/tex], is invested at an annual interest rate, [tex]$r$[/tex], and compounded [tex][tex]$n$[/tex][/tex] times per year, the amount accumulated in the account after [tex]$t$[/tex] years can be found with the equation:
[tex]\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \][/tex]

Javier invested [tex]$\$ 2,350$[/tex] in a savings account for 5 years with a rate of [tex]1.75\%[/tex] compounded every six months. In this situation, what is [tex]n[/tex]?

A. 6
B. 2
C. 0.0175
D. 5



Answer :

To determine the value of [tex]\( n \)[/tex], we need to understand what the phrase "compounded every six months" means in terms of the number of compounding periods in a year.

1. Understanding Compounding Periods:
- Compounding every six months means that interest is added to the principal twice a year, due to each year having twelve months and six going into twelve twice.

2. Interpreting the Compounding Frequency:
- Since a year has 12 months, and compounding occurs every 6 months, we can see that in one year, the interest will be compounded [tex]\( \frac{12}{6} = 2 \)[/tex] times.

Hence, [tex]\( n \)[/tex] represents the number of times the interest is compounded annually. In this situation, interest is compounded twice a year.

Therefore, [tex]\( n = 2 \)[/tex].

The correct answer is [tex]\( \boxed{2} \)[/tex].