Answered

The function [tex]$V=\sqrt{1.223 w}$[/tex] expresses the landing speed, [tex]$V$[/tex] (in feet per second), as a function of the gross weight, [tex][tex]$w$[/tex][/tex] (in pounds), of an aircraft. Write an equation that expresses the gross weight of an aircraft as a function of its landing speed.

A. [tex]$w=\frac{1.23}{V^2}$[/tex]

B. [tex]$w=\left(\frac{V}{1223}\right)^2$[/tex]

C. [tex][tex]$w=\sqrt{1.223 V}$[/tex][/tex]

D. [tex]$w=\frac{V^2}{1.223}$[/tex]



Answer :

To express the gross weight [tex]\( w \)[/tex] of an aircraft as a function of its landing speed [tex]\( V \)[/tex], let's start with the given relationship:

[tex]\[ V = \sqrt{1.223 \, w} \][/tex]

1. First, isolate the square root by squaring both sides of the equation to remove the square root:

[tex]\[ V^2 = 1.223 \, w \][/tex]

2. Next, solve for [tex]\( w \)[/tex] by dividing both sides of the equation by 1.223:

[tex]\[ w = \frac{V^2}{1.223} \][/tex]

Thus, the equation that expresses the gross weight [tex]\( w \)[/tex] as a function of the landing speed [tex]\( V \)[/tex] is:

[tex]\[ w = \frac{V^2}{1.223} \][/tex]

Therefore, the correct option is:

D. [tex]\( w = \frac{V^2}{1.223} \)[/tex]