Answered

If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?

[tex] \square \ m/s^2 [/tex]



Answer :

Let's solve the problem step by step using Newton's Second Law of Motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration. Mathematically, this can be expressed as:

[tex]\[ F = ma \][/tex]

Where:
- [tex]\( F \)[/tex] is the force applied to the object,
- [tex]\( m \)[/tex] is the mass of the object,
- [tex]\( a \)[/tex] is the acceleration of the object.

Given:
- The mass [tex]\( m \)[/tex] of the volleyball is [tex]\( 0.25 \)[/tex] kg.
- The force [tex]\( F \)[/tex] applied to the volleyball is [tex]\( 0.5 \)[/tex] N (Newtons).

We need to find the acceleration [tex]\( a \)[/tex] of the volleyball. Rearranging the equation [tex]\( F = ma \)[/tex] to solve for [tex]\( a \)[/tex], we get:

[tex]\[ a = \frac{F}{m} \][/tex]

Substituting the given values into the equation:

[tex]\[ a = \frac{0.5 \, \text{N}}{0.25 \, \text{kg}} \][/tex]

[tex]\[ a = 2.0 \, \text{m/s}^2 \][/tex]

Therefore, the acceleration of the ball is [tex]\( 2.0 \, \text{m/s}^2 \)[/tex].